How to Serialize and Deserialize JSON in C#

JSON serialization and deserialization in C# has become remarkably straightforward with the System.Text.Json namespace, introduced in .NET Core 3.0 as a modern alternative to Newtonsoft.Json.

The JsonSerializer class provides static methods to convert objects to JSON strings (Serialize) and parse JSON strings back into objects (Deserialize).

For basic serialization, you can simply call JsonSerializer.Serialize(object) on any object, and it will automatically convert public properties into their JSON representation.

Similarly, JsonSerializer.Deserialize<T>(jsonString) converts JSON back into strongly-typed objects. The process becomes even more powerful when combined with custom attributes like [JsonPropertyName] to control property naming and [JsonIgnore] to exclude specific properties from serialization.

When working with more complex scenarios, you can customize the serialization process using JsonSerializerOptions.

This allows you to control various aspects such as case sensitivity, indentation, handling of null values, and custom converters. For example, setting PropertyNameCaseInsensitive = true enables case-insensitive property matching during deserialization, while WriteIndented = true produces formatted JSON output.

It's also worth noting that System.Text.Json is designed with performance in mind, offering better performance compared to Newtonsoft.Json for most scenarios.

Example

// Define a class to serialize
public class Person
{
    public string Name { get; set; }
    [JsonPropertyName("birth_date")]
    public DateTime BirthDate { get; set; }
    [JsonIgnore]
    public int InternalId { get; set; }
}

// Serialization example
Person person = new Person 
{ 
    Name = "John Doe", 
    BirthDate = new DateTime(1990, 1, 1) 
};
string json = JsonSerializer.Serialize(person);

// Deserialization example
Person deserializedPerson = JsonSerializer.Deserialize<Person>(json);

// Using JsonSerializerOptions
var options = new JsonSerializerOptions
{
    WriteIndented = true,
    PropertyNameCaseInsensitive = true,
    PropertyNamingPolicy = JsonNamingPolicy.CamelCase
};
string prettyJson = JsonSerializer.Serialize(person, options);

// Working with collections
List<Person> people = new List<Person> { person };
string jsonArray = JsonSerializer.Serialize(people);
List<Person> deserializedPeople = JsonSerializer.Deserialize<List<Person>>(jsonArray);
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Related

XML (Extensible Markup Language) is a widely used format for storing and transporting data.

In C#, you can create XML files efficiently using the XmlWriter and XDocument classes. This guide covers both methods with practical examples.

Writing XML Using XmlWriter

XmlWriter provides a fast and memory-efficient way to generate XML files by writing elements sequentially.

Example:

using System;
using System.Xml;

class Program
{
    static void Main()
    {
        using (XmlWriter writer = XmlWriter.Create("person.xml"))
        {
            writer.WriteStartDocument();
            writer.WriteStartElement("Person");

            writer.WriteElementString("FirstName", "John");
            writer.WriteElementString("LastName", "Doe");
            writer.WriteElementString("Age", "30");

            writer.WriteEndElement();
            writer.WriteEndDocument();
        }
        Console.WriteLine("XML file created successfully.");
    }
}

Output (person.xml):

<?xml version="1.0" encoding="utf-8"?>
<Person>
    <FirstName>John</FirstName>
    <LastName>Doe</LastName>
    <Age>30</Age>
</Person>

Writing XML Using XDocument

The XDocument class from LINQ to XML provides a more readable and flexible way to create XML files.

Example:

using System;
using System.Xml.Linq;

class Program
{
    static void Main()
    {
        XDocument doc = new XDocument(
            new XElement("Person",
                new XElement("FirstName", "John"),
                new XElement("LastName", "Doe"),
                new XElement("Age", "30")
            )
        );
        doc.Save("person.xml");
        Console.WriteLine("XML file created successfully.");
    }
}

This approach is ideal for working with complex XML structures and integrating LINQ queries.

When to Use Each Method

  • Use XmlWriter when performance is critical and you need to write XML sequentially.
  • Use XDocument when you need a more readable, maintainable, and flexible way to manipulate XML.

Conclusion

Writing XML files in C# is straightforward with XmlWriter and XDocument. Choose the method that best suits your needs for performance, readability, and maintainability.

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Removing duplicates from a list in C# is a common task, especially when working with large datasets. C# provides multiple ways to achieve this efficiently, leveraging built-in collections and LINQ.

Using HashSet (Fastest for Unique Elements)

A HashSet<T> automatically removes duplicates since it only stores unique values. This is one of the fastest methods:

List<int> numbers = new List<int> { 1, 2, 2, 3, 4, 4, 5 };
numbers = new HashSet<int>(numbers).ToList();
Console.WriteLine(string.Join(", ", numbers)); // Output: 1, 2, 3, 4, 5

Using LINQ Distinct (Concise and Readable)

LINQ’s Distinct() method provides an elegant way to remove duplicates:

List<int> numbers = new List<int> { 1, 2, 2, 3, 4, 4, 5 };
numbers = numbers.Distinct().ToList();
Console.WriteLine(string.Join(", ", numbers)); // Output: 1, 2, 3, 4, 5

Removing Duplicates by Custom Property (For Complex Objects)

When working with objects, DistinctBy() from .NET 6+ simplifies duplicate removal based on a property:

using System.Linq;
using System.Collections.Generic;

class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

List<Person> people = new List<Person>
{
    new Person { Name = "Alice", Age = 30 },
    new Person { Name = "Bob", Age = 25 },
    new Person { Name = "Alice", Age = 30 }
};

people = people.DistinctBy(p => p.Name).ToList();
Console.WriteLine(string.Join(", ", people.Select(p => p.Name))); // Output: Alice, Bob

For earlier .NET versions, use GroupBy():

people = people.GroupBy(p => p.Name).Select(g => g.First()).ToList();

Performance Considerations

  • HashSet<T> is the fastest but only works for simple types.
  • Distinct() is easy to use but slower than HashSet<T> for large lists.
  • DistinctBy() (or GroupBy()) is useful for complex objects but may have performance trade-offs.

Conclusion

Choosing the best approach depends on the data type and use case. HashSet<T> is ideal for primitive types, Distinct() is simple and readable, and DistinctBy() (or GroupBy()) is effective for objects.

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In C#, you can format an integer with commas (thousands separator) using ToString with a format specifier.

int number = 1234567;
string formattedNumber = number.ToString("N0"); // "1,234,567"
Console.WriteLine(formattedNumber);

Explanation:

"N0": The "N" format specifier stands for Number, and "0" means no decimal places. The output depends on the culture settings, so in regions where , is the decimal separator, you might get 1.234.567.

Alternative:

You can also specify culture explicitly if you need a specific format:

using System.Globalization;

int number = 1234567;
string formattedNumber = number.ToString("N0", CultureInfo.InvariantCulture);
Console.WriteLine(formattedNumber); // "1,234,567"
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