How to Add or Subtract Days, Months, or Years from a Date in C#

Manipulating dates is a common task in C# applications, whether for scheduling, logging, or calculations.

The DateTime and DateOnly structures provide built-in methods to add or subtract days, months, years, hours, and minutes efficiently.

Adding and Subtracting Days

Use the AddDays method to modify a DateTime instance:

using System;

class Program
{
    static void Main()
    {
        DateTime today = DateTime.Now;
        DateTime nextWeek = today.AddDays(7);
        DateTime lastWeek = today.AddDays(-7);

        Console.WriteLine($"Today: {today:yyyy-MM-dd HH:mm}");
        Console.WriteLine($"Next Week: {nextWeek:yyyy-MM-dd HH:mm}");
        Console.WriteLine($"Last Week: {lastWeek:yyyy-MM-dd HH:mm}");
    }
}

Adding and Subtracting Months

Use the AddMonths method to adjust the month while automatically handling month-end variations:

DateTime currentDate = new DateTime(2025, 3, 31);
DateTime nextMonth = currentDate.AddMonths(1);
DateTime previousMonth = currentDate.AddMonths(-1);

Console.WriteLine($"Current Date: {currentDate:yyyy-MM-dd HH:mm}");
Console.WriteLine($"Next Month: {nextMonth:yyyy-MM-dd HH:mm}");
Console.WriteLine($"Previous Month: {previousMonth:yyyy-MM-dd HH:mm}");

Adding and Subtracting Years

Use the AddYears method to adjust the year, handling leap years automatically:

DateTime date = new DateTime(2024, 2, 29);
DateTime nextYear = date.AddYears(1);
DateTime previousYear = date.AddYears(-1);

Console.WriteLine($"Original Date: {date:yyyy-MM-dd HH:mm}");
Console.WriteLine($"Next Year: {nextYear:yyyy-MM-dd HH:mm}");
Console.WriteLine($"Previous Year: {previousYear:yyyy-MM-dd HH:mm}");

Adding and Subtracting Hours

Use the AddHours method to modify the hour component:

DateTime now = DateTime.Now;
DateTime inFiveHours = now.AddHours(5);
DateTime fiveHoursAgo = now.AddHours(-5);

Console.WriteLine($"Current Time: {now:yyyy-MM-dd HH:mm}");
Console.WriteLine($"In 5 Hours: {inFiveHours:yyyy-MM-dd HH:mm}");
Console.WriteLine($"5 Hours Ago: {fiveHoursAgo:yyyy-MM-dd HH:mm}");

Adding and Subtracting Minutes

Use the AddMinutes method to modify the minute component:

DateTime currentTime = DateTime.Now;
DateTime inThirtyMinutes = currentTime.AddMinutes(30);
DateTime thirtyMinutesAgo = currentTime.AddMinutes(-30);

Console.WriteLine($"Current Time: {currentTime:yyyy-MM-dd HH:mm}");
Console.WriteLine($"In 30 Minutes: {inThirtyMinutes:yyyy-MM-dd HH:mm}");
Console.WriteLine($"30 Minutes Ago: {thirtyMinutesAgo:yyyy-MM-dd HH:mm}");

Using DateOnly for Simpler Date Manipulation

For applications that don't require time components, DateOnly (introduced in .NET 6) provides a cleaner approach:

DateOnly today = DateOnly.FromDateTime(DateTime.Now);
DateOnly futureDate = today.AddDays(30);

Console.WriteLine($"Today: {today}");
Console.WriteLine($"30 Days Later: {futureDate}");

Conclusion

C# provides built-in methods for adjusting dates effortlessly. Whether working with DateTime or DateOnly, these functions ensure accurate date calculations, even when dealing with leap years, month-end scenarios, hours, and minutes.

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Related

String interpolation, introduced in C# 6.0, provides a more readable and concise way to format strings compared to traditional concatenation (+) or string.Format(). Instead of manually inserting variables or placeholders, you can use the $ symbol before a string to directly embed expressions inside brackets.

string name = "Walt";
string job = 'Software Engineer';

string message = $"Hello, my name is {name} and I am a {job}";
Console.WriteLine(message);

This would produce the final output of:

Hello, my name is Walt and I am a Software Engineer

String interpolation can also be chained together into a multiline string (@) for even cleaner more concise results:

string name = "Walt";
string html = $@"
    <div>
        <h1>Welcome, {name}!</h1>
    </div>";
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Storing passwords as plain text is dangerous. Instead, you should hash them using a strong, slow hashing algorithm like BCrypt, which includes built-in salting and resistance to brute-force attacks.

Step 1: Install BCrypt NuGet Package

Before using BCrypt, install the BCrypt.Net-Next package:

dotnet add package BCrypt.Net-Next

or via NuGet Package Manager:

Install-Package BCrypt.Net-Next

Step 2: Hash a Password

Use BCrypt.HashPassword() to securely hash a password before storing it:

using BCrypt.Net;

string password = "mySecurePassword123";
string hashedPassword = BCrypt.HashPassword(password);

Console.WriteLine(hashedPassword); // Output: $2a$12$...

Step 3: Verify a Password

To check a user's login attempt, use BCrypt.Verify():

bool isMatch = BCrypt.Verify("mySecurePassword123", hashedPassword);
Console.WriteLine(isMatch); // Output: True

Ensuring proper hashing should be at the top of your list when it comes to building authentication systems.

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Removing duplicates from a list in C# is a common task, especially when working with large datasets. C# provides multiple ways to achieve this efficiently, leveraging built-in collections and LINQ.

Using HashSet (Fastest for Unique Elements)

A HashSet<T> automatically removes duplicates since it only stores unique values. This is one of the fastest methods:

List<int> numbers = new List<int> { 1, 2, 2, 3, 4, 4, 5 };
numbers = new HashSet<int>(numbers).ToList();
Console.WriteLine(string.Join(", ", numbers)); // Output: 1, 2, 3, 4, 5

Using LINQ Distinct (Concise and Readable)

LINQ’s Distinct() method provides an elegant way to remove duplicates:

List<int> numbers = new List<int> { 1, 2, 2, 3, 4, 4, 5 };
numbers = numbers.Distinct().ToList();
Console.WriteLine(string.Join(", ", numbers)); // Output: 1, 2, 3, 4, 5

Removing Duplicates by Custom Property (For Complex Objects)

When working with objects, DistinctBy() from .NET 6+ simplifies duplicate removal based on a property:

using System.Linq;
using System.Collections.Generic;

class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
}

List<Person> people = new List<Person>
{
    new Person { Name = "Alice", Age = 30 },
    new Person { Name = "Bob", Age = 25 },
    new Person { Name = "Alice", Age = 30 }
};

people = people.DistinctBy(p => p.Name).ToList();
Console.WriteLine(string.Join(", ", people.Select(p => p.Name))); // Output: Alice, Bob

For earlier .NET versions, use GroupBy():

people = people.GroupBy(p => p.Name).Select(g => g.First()).ToList();

Performance Considerations

  • HashSet<T> is the fastest but only works for simple types.
  • Distinct() is easy to use but slower than HashSet<T> for large lists.
  • DistinctBy() (or GroupBy()) is useful for complex objects but may have performance trade-offs.

Conclusion

Choosing the best approach depends on the data type and use case. HashSet<T> is ideal for primitive types, Distinct() is simple and readable, and DistinctBy() (or GroupBy()) is effective for objects.

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